To extract MIME attachments from a received email message in Go, you can use the net/mail
and mime/multipart
packages. Here's an example of how you can accomplish this:
package main
import (
"io"
"log"
"net/mail"
"mime/multipart"
"os"
)
func main() {
// Open the email file
file, err := os.Open("email.eml") // Replace with the path to your email file
if err != nil {
log.Fatal(err)
}
defer file.Close()
// Parse the email using net/mail
msg, err := mail.ReadMessage(file)
if err != nil {
log.Fatal(err)
}
// Check if the email has multiple parts (which would indicate MIME attachments)
if msg.Header.Get("Content-Type") == "multipart/mixed" {
mr := multipart.NewReader(msg.Body, msg.Header.Get("Content-Type"))
// Iterate over each part in the email
for {
p, err := mr.NextPart()
if err == io.EOF {
break
}
if err != nil {
log.Fatal(err)
}
// Determine the filename of the part
filename := p.FileName()
if filename != "" {
// Create a new file to save the attachment
file, err := os.Create(filename)
if err != nil {
log.Fatal(err)
}
defer file.Close()
// Copy the attachment data to the new file
_, err = io.Copy(file, p)
if err != nil {
log.Fatal(err)
}
log.Println("Attachment saved:", filename)
}
}
}
}
In this example, the email file is read using os.Open
, and the mail.ReadMessage
function from the net/mail
package is used to parse the email. If the email has a Content-Type of "multipart/mixed", indicating the presence of attachments, a multipart.Reader
is created using the email's body and Content-Type.
The code then iterates over each part in the email using mr.NextPart()
, and checks if the part has a non-empty FileName()
(indicating an attachment). A new file is created using os.Create
, and the attachment data is copied to the new file using io.Copy
. Finally, the filename of the attachment is printed to the console.
Make sure to replace "email.eml"
with the path to your email file.