How to escape special characters in regular expressions in Golang?

In Golang, you can escape special characters within regular expressions using the regexp.QuoteMeta function.

Here's an example that demonstrates how to escape special characters in a regular expression pattern:

package main

import (
	"fmt"
	"regexp"
)

func main() {
	pattern := regexp.QuoteMeta(`[foo] bar (baz)`)
	fmt.Println(pattern)
}

Output:

\[foo\] bar \(baz\)

The regexp.QuoteMeta function adds a backslash \ before each special character present in the input pattern, so that those characters are treated as literal characters when the regular expression is matched.