How to enforce encapsulation and access control in embedded structs in Go?

In Go, encapsulation and access control can be enforced in embedded structs using a combination of naming conventions and field visibility modifiers. Here are some steps to follow:

  1. Create a struct that represents the embedded struct. This struct will hold the data and methods specific to the embedded struct. Let's call it embeddedStruct.

  2. Define the fields and methods for the embeddedStruct struct, keeping in mind the encapsulation requirements.

  3. Within the parent struct, define an embedded field of type embeddedStruct. This creates an "is-a" relationship between the parent struct and the embedded struct.

  4. Make the field of the embedded struct private by starting its name with a lowercase letter. This ensures that the field is not directly accessible from outside the parent struct.

Here's an example implementation:

// embeddedStruct represents the embedded struct with encapsulated fields and methods. type embeddedStruct struct { privateField int } // PublicMethod is a method of the embedded struct. func (es *embeddedStruct) PublicMethod() { // Access to the privateField is allowed here. es.privateField = 10 } // ParentStruct represents the parent struct embedding the embeddedStruct. type ParentStruct struct { embeddedStruct publicField int } func main() { ps := ParentStruct{} // Access to the embedded struct's privateField is not allowed here. // ps.privateField = 5 // This will cause a compilation error. // Access to the embedded struct's privateField is allowed via public methods. ps.PublicMethod() // Successfully sets privateField to 10 // The parent struct's publicField can be directly accessed. ps.publicField = 20 }

In this example, ParentStruct embeds the embeddedStruct, allowing access to publicField directly but restricting access to privateField. The publicField can be accessed and modified directly. However, access to privateField is only allowed through PublicMethod().